c++ STL map

dictionary data structure.

 

example with question answer :

Problem
Given names and phone numbers, assemble a phone book that maps names to their respective phone numbers.

After this dictionary is created you will then be given an unknown number of names to query your phone book for; for each queried, print the associated entry from your phone book (in the form name=PhoneNumber ) or  ( Not Found) if there is no entry for .

Input Format

The first line contains an integer,N , denoting the number of entries in the phone book.
Each of the subsequent lines describes an entry in the form of space-separated values on a single line. The first value is a friend’s , and the second value is an -digit .

After the lines of phone book entries, there are an unknown number of lines of queries. Each line (query) contains a to look up, and you must continue reading lines until there is no more input.

 

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
#include <map>
using namespace std;
int main() {
/* Enter your code here. Read input from STDIN. Print output to STDOUT */
int N;
cin>>N;
map<string,int> dict;
for(int i = 0; i < N; i++){
string name;
int number;
cin>>name;
cin>>number;
dict[name] = number;
}
string line;
vector<string> inp;
//remove top new line
getline(std::cin, line);
while (getline(std::cin, line)){
inp.push_back(line);
}
for(int i = 0; i < inp.size(); i++){
if(dict.find(inp[i]) != dict.end()){
cout<<inp[i]<<"="<<dict[inp[i]]<<endl;
}
else{
cout<<"Not found"<<endl;
}
}
return 0;
}